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Lake Santee is an unincorporated town and census-designated place in Decatur and Franklin counties, Indiana, United States. As of the 2010 census, it had a population of 820.[3]

Lake Santee, Indiana
Census-designated place
Location of Lake Santee in Decatur County and Franklin County, Indiana.
Lake Santee
Coordinates: 39°24′36″N 85°18′27″W
CountryUnited States
StateIndiana
CountyDecatur, Franklin
TownshipFugit, Salt Creek
Area
  Total2.82 sq mi (7.30 km2)
  Land2.46 sq mi (6.38 km2)
  Water0.36 sq mi (0.92 km2)
Elevation
1,015 ft (309 m)
Population
 (2020)
  Total889
  Density360.94/sq mi (139.34/km2)
ZIP code
47240
FIPS code18-41444[2]

History


Lake Santee was built up in the 1960s as a housing development centered on a reservoir of the same name.[4]


Geography


Lake Santee is located at 39°24′36″N 85°18′27″W in southeastern Indiana. It is situated 13 miles (21 km) northeast of Greensburg and 12 miles (19 km) northwest of Batesville.

According to the U.S. Census Bureau, the CDP has a total area of 2.8 square miles (7.3 km2), of which 2.5 square miles (6.4 km2) is land and 0.35 square miles (0.9 km2), or 12.60%, is water. The water area consists entirely of Lake Santee, the reservoir.[5]


Demographics


Historical population
CensusPop.
2020889
U.S. Decennial Census[6]

References


  1. "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  2. "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  3. "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Lake Santee CDP, Indiana". United States Census Bureau. Retrieved October 4, 2012.
  4. "History of Lake Santee". Retrieved 7 September 2014.
  5. "Geographic Identifiers: 2010 Demographic Profile Data (G001): Lake Santee CDP, Indiana". United States Census Bureau. Retrieved October 4, 2012.
  6. "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.





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