Seymourville is an unincorporated community in Grant County, West Virginia, United States. Seymourville is 4.5 miles (7.2 km) north of Petersburg.
Seymourville, West Virginia | |
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Unincorporated community | |
![]() ![]() Seymourville ![]() ![]() Seymourville | |
Coordinates: 39°03′25″N 79°06′32″W | |
Country | United States |
State | West Virginia |
County | Grant |
Elevation | 1,030 ft (310 m) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
Area code(s) | 304 & 681 |
GNIS feature ID | 1555594[1] |
Municipalities and communities of Grant County, West Virginia, United States | ||
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County seat: Petersburg | ||
City | ![]() | |
Town | ||
Unincorporated communities |
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Footnotes | ‡This populated place also has portions in an adjacent county or counties | |
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