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Rutland Township is one of twelve townships in Humboldt County, Iowa, USA.[1] As of the 2000 census, its population was 529.

Rutland Township
Township
Location in Humboldt County
Coordinates: 42°40′17″N 94°00′19″W
Country	United States
State	Iowa
County	Humboldt
Established	1867
Area
• Total	34.8 sq mi (90 km2)
• Land	34.5 sq mi (89 km2)
• Water	0.3 sq mi (0.8 km2)
Elevation	1,152 ft (351 m)
Population  (2000)
• Total	529
• Density	15/sq mi (6/km2)
Time zone	UTC-6 (CST)
• Summer (DST)	UTC-5 (CDT)
ZIP codes	50582 (Rutland)
GNIS feature ID	0468648

History

Rutland Township was organized in 1867.[2]

Geography

According to the United States Census Bureau, Rutland Township covers an area of 34.8 square miles (90 km²); 34.5 square miles (89 km²) of this is land, and the remaining 0.3 square miles (0.78 km²) is water.

Cities, towns, villages

• Rutland

Adjacent townships

• Delana Township (north)
• Humboldt Township (northeast)
• Grove Township (east)
• Beaver Township (southeast)
• Corinth Township (south)
• Weaver Township (southwest)
• Avery Township (west)
• Wacousta Township (northwest)

Cemeteries

The township contains Rutland Township Cemetery.

Political districts

• Iowa's 4th congressional district
• State House District 4

References

• United States Census Bureau 2008 TIGER/Line Shapefiles
• United States Board on Geographic Names (GNIS)
• United States National Atlas

External links

• US-Counties.com
• City-Data.com

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