Oak Grove Township is one of eleven townships in Benton County, Indiana. As of the 2020 census, its population was 1,551 and it contained 690 housing units.[3] It was one of the first three townships originally created by the county's commissioners in 1840.[4] It takes its name from White Oak Grove which grew southwest of Oxford.[5]

Oak Grove Township
Township
Location of Oak Grove Township in Benton County
Coordinates: 40°31′09″N 87°15′54″W
Country	United States
State	Indiana
County	Benton
Organized	July 1840
Government
• Type	Indiana township
Area
• Total	35.53 sq mi (92.0 km2)
• Land	35.51 sq mi (92.0 km2)
• Water	0.02 sq mi (0.05 km2)
Elevation [1]	748 ft (228 m)
Population  (2020)
• Total	1,551
• Density	43.6/sq mi (16.8/km2)
Time zone	UTC-5 (EST)
• Summer (DST)	UTC-4 (EDT)
FIPS code	18-55620[2]
GNIS feature ID	453681

Geography

According to the 2020 census, the township has a total area of 35.53 square miles (92.0 km²), of which 35.51 square miles (92.0 km²) (or 99.94%) is land and 0.02 square miles (0.052 km²) (or 0.06%) is water.[3]

Cities and towns

• Oxford

Unincorporated towns

• Fargo

Adjacent townships

• Bolivar (east)
• Center (north)
• Grant (west)
• Pine (northeast)
• Adams Township, Warren County (southeast)
• Pine Township, Warren County (southwest)

Major highways

• U.S. Route 52
• Indiana State Road 55
• Indiana State Road 352

Cemeteries

The township contains two cemeteries: Justus and Oxford.

References

Citations

Sources

• United States Census Bureau cartographic boundary files
• U.S. Board on Geographic Names

External links

Wikimedia Commons has media related to Oak Grove Township, Benton County, Indiana.

• Indiana Township Association
• United Township Association of Indiana