Cloverdale is an unincorporated community in Osceola County, Iowa, United States.[1] It is located 5 miles southeast of the county seat Sibley, and 10 miles from the Iowa-Minnesota border. [2]
Cloverdale, Iowa | |
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Unincorporated Community | |
![]() ![]() Cloverdale, Iowa Location of Cloverdale, Iowa Show map of Iowa![]() ![]() Cloverdale, Iowa Cloverdale, Iowa (the United States) Show map of the United States | |
Coordinates: 43.3469151°N 95.6858470°W / 43.3469151; -95.6858470 | |
Country | ![]() |
State | ![]() |
County | Osceola County |
Elevation | 466 m (1,529 ft) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
Zip code | 51249 |
Area code(s) | 712 |
GNIS feature ID | 455489 |
Cloverdale's population was 50 in 1925.[3]
Municipalities and communities of Osceola County, Iowa, United States | ||
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County seat: Sibley | ||
Cities | ![]() | |
Townships |
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Unincorporated communities |
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