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Benton Township is one of sixteen townships in Elkhart County, Indiana. As of the 2020 census, its population was 3,200, up from 2,963 at the previous census.[3]

Benton Township
Township
Location of Benton Township in Elkhart County
Coordinates: 41°28′55″N 85°42′27″W
CountryUnited States
StateIndiana
CountyElkhart
Government
  TypeIndiana township
Area
  Total35.9 sq mi (93 km2)
  Land35.84 sq mi (92.8 km2)
  Water0.06 sq mi (0.2 km2)
Elevation853 ft (260 m)
Population
 (2020)
  Total3,200
  Density89/sq mi (34/km2)
FIPS code18-04798[2]
GNIS feature ID453105

According to the 2020 "ACS 5-Year Estimates Data Profiles", 70.1% of the township's population spoke only English, while 23.7 spoke an "other [than Spanish] Indo-European language"[4] (basically Pennsylvania German/German).


Geography


According to the 2010 census, the township has a total area of 35.9 square miles (93 km2), of which 35.84 square miles (92.8 km2) (or 99.83%) is land and 0.06 square miles (0.16 km2) (or 0.17%) is water.[3]


Cities and towns



Unincorporated towns



Adjacent townships



Major highways



Cemeteries


The township contains two cemeteries: Brown and Hire.


Demographics


Historical population
CensusPop.
20102,963
20203,2008.0%
U.S. Censuses: 2010,[3]
and 2020[4]

References


  1. "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
  2. "U.S. Census website". United States Census Bureau. Retrieved 2008-01-31.
  3. "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on 2020-02-12. Retrieved 2013-05-10.
  4. "Benton township, Elkhart County, Indiana". data.census.gov. Retrieved 2022-03-21.






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