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The Borough of Sebastopol was a local government area about 4 kilometres (2 mi) south of the regional city of Ballarat, Victoria, Australia. The borough covered an area of 7.61 square kilometres (2.9 sq mi), and existed from 1864 until 1994.

Borough of Sebastopol
Victoria
Population7,800 (1992)[1]
 • Density1,025/km2 (2,655/sq mi)
Established1864
Area7.61 km2 (2.9 sq mi)
Council seatSebastopol
CountyGrenville

Sebastopol was incorporated as a borough on 1 October 1864.[2] On 6 May 1994, the Borough of Sebastopol was abolished, and, along with the City of Ballaarat, the Shire of Ballarat, and parts of the Shires of Bungaree, Buninyong, Grenville and Ripon, was merged into the newly created City of Ballarat.[3]


Population


Year Population
19543,265
19583,480*
19614,663
19664,966
19715,268
19765,941
19816,462
19867,011
19917,527

* Estimate in the 1958 Victorian Year Book.


References


  1. Australian Bureau of Statistics, Victoria Office (1994). Victorian Year Book. pp. 49–52. ISSN 0067-1223.
  2. Victorian Municipal Directory. Brunswick: Arnall & Jackson. 1992. Accessed at State Library of Victoria, La Trobe Reading Room.
  3. Australian Bureau of Statistics (1 August 1995). Victorian local government amalgamations 1994-1995: Changes to the Australian Standard Geographical Classification (PDF). Commonwealth of Australia. ISBN 0-642-23117-6. Retrieved 5 January 2008.




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